lewis structure of io3-

1 ANSWERS

1. amomipais82
   

   Hi There,
   First you need to determine the charge on the polyanion. Then, assume that the oxygens are at a valence of -2. From those two bits of information, determine the oxidation state of the iodine.
   
   Now, start at the iodine and put seven electrons around it. That is the ground state for iodine. Take away as many electrons as you need to get to the oxidation state of the iodine that you determined above. (it isn't 7....) Do the same for the oxygens but add two electrons to it's ground state.
   
   Put it together... You should end up with one excess electron charge which gives the complex it's -1 valency.

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